Question

three equal cubes are placed adjacently in a row. the ratio of total surface area of the resulting cuboid to that of the sum of the surface areas of three cubes is​

Answer 1

Answer:

чσu cαn gєt thє αnѕwєr frσm thє pαgє αttαchєd hєrє.

Answer 2

Answer:

7:9

Step-by-step explanation:

Let a be the side of three equal cubes

∴ Surface area of 3 cubes

= 3 x 6a2 = 18a2

and length of so formed cuboid = 3a

Breadth = a

and height = a

∴ Surface area = 2(lb + bh + hl)

= 2[3a x a + a x a+a x 3a] = 2[3a2 + a2 + 3a2] = 2 x 7a2 = 14a2

∴ Ratio in the surface areas of cuboid and three cubes = 14a2 : 18a2= 7:9