Question

Three equal cubes, each of edge 10 cm, are placed adjacent to each other. Find the volume and surface area of the new solid formed?​

Answer 1

3000cm³..,....................

Answer 2

Answer:

Three cubes of edge 10 cm are joined to form a cuboid-

Therefore,

Length of cuboid (l)=10+10+10=30cm

Breadt of cuboid (b)=10cm

Height of cuboid (h)=10cm

∴ Total surface area of cuboid (A)=2(lb+bh+hl)

⇒A=2[(30×10)+(10×10)+(10×30)]

⇒A=2(300+100+300)

⇒A=1400cm2

Hence the surface area of resulting cuboid is 1400cm2.

As the side of each small cube is 10cm.

Therefore, the area of each small cube (a) will be-

a=6(side)2

⇒a=6×102=600cm2

Sum of surface area of all three cubes =600+600+600=1800cm2

Now, ratio of surface are of resulting cuboid to the sum of the surface areas of three cube =18001400=97

Hence the ratio of surface are of resulting cuboid to the sum of the surface areas of three cube is 7:9.