Three equal cubes of l= 2cm are placed adjacent to each other in a row find tsa of new cuboit
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Answered by
0
Let the side of the cube be ‘x’ units
Total surface of cuboid = 6x2 sq units
Sum of surface ares of three cubes = 3(6x2)= 18x2
Since three equal cubes are placed adjacently, length of the cube will be 3x units
Breadth = x units and height = x units
Total surface area of the cuboid = 2(lb + bh + hl) sq units
Ratio of total surface area of new cuboid to that of the surface area of the three cubes
Hence the ratio is 7:9
Answered by
3
Length of each side of cube = 2cm
Length of the cuboid = 2×3 = 6 cm
Breadth = Height = 2 cm
( breadth and height are of same values )
Therefore , Total surface area
= 2(ab+bc+ac)
= 2 ( 6×2 + 2×2 + 6×2 )
= 2 ( 12+4+12)
= 2× 28
= 56 sq. cm
Length of the cuboid = 2×3 = 6 cm
Breadth = Height = 2 cm
( breadth and height are of same values )
Therefore , Total surface area
= 2(ab+bc+ac)
= 2 ( 6×2 + 2×2 + 6×2 )
= 2 ( 12+4+12)
= 2× 28
= 56 sq. cm
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