Question

three equal masses A, B and C are pulled with a constant force f they are connected to each other with strings the ratio of the tension between AB and BC is​

Answer 1

Ratio of tension between AB & BC = 1 : 1

Explanation:

Given :

3 equal masses A, B, C connected to each other through strings (thus forming equilateral triangle)

Force of pull on each of A, B, & C = f

To find : Ratio of tension between AB : tension between BC

Solution :

Step-1 : As deduced from the question, the equilibrium condition is established since identical force is acting on equal masses. Hence they will be spaced in equilateral triangular position. Refer sketch attached.

Step-2 : Since tension (T) will be same in each of the limbs of the equilateral triangle, the ratio of tension on AB : tension on BC = 1 : 1 (in terms of magnitude with an angular separation of 60 degrees in space).