Question

Three equal masses m are placed at the three vertices of an equilateral triangle of side a .The gravitational force exerted by this system on another particle of mass m placed at the mid point of a side
a. Gm^2/3a ^2
b.4Gm^2 /3a^2
c.Gm^2/a^2
d. Gm^2/3a^2​

Answer 1

Answer:

Correct option is

B

3a

2

4Gm

2

Explanation:

Correct option is

B

3a

2

4Gm

2

Force in OA=

a

2

4Gm

2

Force in OB=

a

2

4Gm

2

As equal and opposite forces cancel each other

Force in OC=

[(

3

/2)a]

2

Gm

2

=

3a

2

4Gm

2

So net gravitational force on m=

3a

2

4Gm

2

solution

Answer 2

Explanation:

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