Three equal masses of m kg each are fixed at the vertices of an
equilateral triangle ABC of side a. What is the force acting on each mass?
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From Figure, the gravitational force on mass 2m at G due to mass at A is F1 = G m × 2m1^2 = 2Gm^2 along GAGravitational force on mass 2 m at G due to mass ...
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