Three equal point charges of 2 µC are in free space at (0,0,0) ,(2,0,0
Answers
Answered by
0
Answer:
pls mark me
Explanation:
The distance between two charges is r=
(2−1)
2
+(3−1)
2
+(1−1)
2
=
5
By Coulomb's law, the force between two charges is F=
4πϵ
0
1
r
2
q
1
q
2
=(9×10
9
)(
5
3×10
−6
×3×10
−6
)=16.2×10
−3
N
Answered by
0
Answer:
000+200
= 200 is the right answer
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