Question

Three equal weights of 3 kg each are hanging on a string Passing over a frictionless pulley as shown in figure.

Answer 1

Please provide us with the figure????

Answer 2

Explanation:

Let us take the three masses and the strings as a system.

Let the tension in the string be T.

Equation of motion are as follows-

T−mg=ma

2mg−T=2ma

⇒ a=3g

Now let us work from the ground reference for the block ∣∣∣

Let tension in this string be T1

equation of its motion is-

mg−T1=ma

⇒ T1=2mg/3

T1=20N