Question

Three equal weights of mass 2 kg each are hanging on a string passing over a fixed pulley

Answer 1

Answer:

Explanation:

LET TENSION IN STRING CONNECTING A TO B BE T1 AND THE REQUIRED TENSION BE T

rnC=2g-T=2a

rnB=2g-T1+T=2a

rn and B=T1-2g=a

rnandding the three eq. we get

rna=g/3

rnputting in eq. of c we get T=13.08 N≈ 13 N