Question

Three equal weights of mass 2 kg each are hanging on a string passing over a fixed pulley as shown in the figure. The tension in the string connecting the weights B and C is
(a) zero
(b) 13 N
(c) 3.3 N
(d) 19.6 N
***EXPLAIN THE ANSWER PLZZ***​

Answer 1

he Free body diagram of the system is shown.

For block A:  T−mg=ma

T−2g=2a        

We get  T=2a+2g

For block B + C system : mg+mg−T=(m+m)a

2g+2g−T=(2+2)a  

⟹4g−T=4a

Or  4g−2a−2g=4a

Or  2g=6a

This gives a=g/3

For block C:  mg−T  

′

=ma

2g−T  

′

=2a

Or  2g−T  

′

=  

3

2g

​  

 

Thus we get  T  

′

=4g/3=  

3

4×10

​  

=13N

Got this from another reliable source