Question

Three equally charged small objects are placed as shown in figure the object A exerts an electric force on object B equal to 3 into 10 to the power minus 6 Newton .what electric force does C exerts on B? what is the net electric force on B?

Answer 1

Given that,

Three equally charged small objects.

The object A exerts an electric force on object B is

$F_{AB}=3\times10^{-6}\ N$

Suppose, Three equally charged small objects are placed at equal distance.

We know that,

The magnitude of the electrostatic force F between point charges q and q' separated by a distance r is given by Coulomb’s law.

According to Newton’s third law,

The force on q is equal in magnitude and opposite in direction to the force it exerts on q'.

So, The object C exerts the same magnitude and opposite direction of electric force on B.

The electric force on B due to C

$F_{CB}=-3\times10^{-6}$

We need to calculate the net electric force on B

Using formula of net electric force

$F=F_{AB}+F_{CB}$

Put the value into the formula

$F= 3\times10^{-6}-3\times10^{-6}$

$F=0$

Hence, The electric force on B due to C is $-3\times10^{-6}$

The net electric force on B is zero.

Answer 2

Answer:hope the answer will help you

Explanation: