Question

three equations of motion by derivation​

Answer 1

Answer:

• Acceleration = Change in velocity/Time Taken

Acceleration = Change in velocity/Time TakenTherefore, Acceleration = (Final Velocity-Initial Velocity) / Time Taken

Acceleration = Change in velocity/Time TakenTherefore, Acceleration = (Final Velocity-Initial Velocity) / Time TakenHence, a = v-u /t or at = v-u

Acceleration = Change in velocity/Time TakenTherefore, Acceleration = (Final Velocity-Initial Velocity) / Time TakenHence, a = v-u /t or at = v-uTherefore, we have: v = u + at

• Average velocity = (final velocity + initial velocty)/2 = (v+u)/2

Hence, Distance (s) = [(v+u)/2] × [(v-u)/a]

or s = (v² – u²)/2a

or 2as = v² – u²

• or v² = u² + 2asDistance = Average velocity × Time. Also, Average velocity = (u+v)/2

Therefore, Distance (s) = (u+v)/2 × t

Also, from v = u + at, we have:

s = (u+u+at)/2 × t = (2u+at)/2 × t

s = (2ut+at²)/2 = 2ut/2 + at²/2

or s = ut +½ at²

hope it'll help u......