Question

three fair coin are tossed together find the probability of getting all heads at least one tail at most one head
at most two tails

Answer 1

Answer:

1) 1 / 8

2) 7 / 8

3) 1 / 2

4) 7/8

Step-by-step explanation:

Heya friend,

Here we go :

When 3 fair coins are tossed together, the sample space would be :

{ HHH , HHT , HTH , THH , TTT , TTH , THT , HTT }

So,

Total outcomes = 8

Now,

Let's see each part :

1 ) Probability of all heads

Favorable case = {HHH}

Probability = $\frac{1}{8}$

2 ) Probability of at least one tail

Here the favorable cases, would the outcomes with 1 tail, 2 tails or all tails. So,

Favorable case(s) = {HHT , HTH , THH , TTH , THT , HTT , TTT}

Probability = $\frac{7}{8}$

3 ) Probability of at most 1 head

Here the favorable cases would be the outcomes with one head or no head. So,

Favorable case(s) = {TTT , TTH , THT , HTT}

Probability =  $\frac{4}{8}$

                  = $\frac{1}{2}$

4) Probability of at most 2 tails

Here, the favorable cases would be outcomes with 2 tails, 1 tail or no tail.

So,

Favorable cases = {HHH , HTH , HHT , THH , TTH , THT , HTT}

Probability = $\frac{7}{8}$

Thanks !

#BAL #answerwithquality

Answer 2

Answer:

Answer:

1) 1 / 8

2) 7 / 8

3) 1 / 2

4) 7/8

Step-by-step explanation: