three fair coins are tossed simultaneously what is the probability of getting 1. at least 2 tails 2. one head 3. at most one head
Answers
Answered by
2
Answer:
total number of outcome is 4
Step-by-step explanation:
1/7
Answered by
1
Answer:
1) 1/8
2)1/2
3)1/2
Step-by-step explanation:
sample space
HHH , HHT,HTH,THH,HTT,THT,TTH,TTT
P(E) = no. of favourable outcomes/ total no. of possible outcomes
1) p(3 heads) =1/8
2) p(at least 2 tails) =4/8=1/2
3)p(at least 2 heads) = 4/8=1/2
hope it helps you ....
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