three farmers have 490 kg 588 kg and 882 kg of wheat respectively find the maximum capacity of a bag so that the wheat can be packed in exact number of bags find also from minimum number of bags required to pack his wheat
please answer fast it's urgent
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Answered by
6
Answer:
98
Step-by-step explanation:
490=2*7*7*5
588=2*2*3*7*7
882=2*3*3*7*7
HCF=7*7*2
=98 bags
hope it helps you
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