Question

Three forces 5 N , 10 N and 15 N act along three sides of
an equilateral triangle AB, BC and CA. Side AB being
horizontal. The resultant of system is

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Answer 1

Answer:

Explanation:

ab=5 multiplied by 10=50

bc=10 multiplied by 15=150

ca=15 multiplied by 5=75

Answer 2

15 N

The perpendicular distance between point O and sides AB, BC, and AC will be the same (say r). If the total moment of force around point O is 0, the torque will be zero. Forces P, 2P, and 3P act cyclically along the 3 sides of an equilateral ABC Icy and the resultant's direction. In cyclic order, cecally around 3 sides of the an equilateral triangle ABC.