Question

Three forces act on a body kept at origin such that their resultant is F=200N along y axis.if the forces are F1=100 N, 30° to the right of F, F2 =200 N, 50° to the left of F, then the magnitude and direction of F3 is :

Answer 1

Answer:

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Explanation:

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Answer 2

$\sf\large{\underline{\pink{SoLuTiOn}}}$

$\sf{\underline{From\: Figure}}$

$\sf{F_{1} + F_{2} + F_{3} = 200\: N}$

$\sf{100\:N+ 200\:N + F_{3} = 200\:N}$

$\sf\orange{F_{3} = -100\:N}$

Negative sign of Force ( $\sf\blue{F_{3}}$ ) tells that $\sf\blue{F_{3}}$ is just opposite of $\sf\blue{F_{1}}$ . In order of make the resultant 200 N

$\sf\bold{\underline{\green{Therefore,}}}$

Magnitude of $\sf\orange{F_{3} = 100 N}$

Direction of $\sf\orange{F_{3} = 100°}$ left of $\sf\blue{F_{2}}$ or 150° left of F(Resultant).