Three forces F1 F2 and F3 act on a body of mass M such that the body is in equilibrium and its acceleration is zero . If the forces F2 and F3 and mutually perpendicular and F1 is removed then what will be the acceleration of the body?
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Heres ur answer..
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The particle remains stationary on the application of three forces that means the resultant force is 0.
This implies
F1 = - (F2 + F3)
Since, if the force F1 is removed, the forces acting are F2 and F3, the resultant of which has the magnitude of F1.
Therefore, the acceleration of the particle is F1/m
This implies
F1 = - (F2 + F3)
Since, if the force F1 is removed, the forces acting are F2 and F3, the resultant of which has the magnitude of F1.
Therefore, the acceleration of the particle is F1/m
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