Three forces F1, F2, and F3, act on an object simultaneously. These force vectors are shown in the following
free-body diagram. In which direction does the object accelerate? [Length of vector = magnitude of force)
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2
Answer:
F1 + F2 + F3 = 0
F2 + F3 = (-)F1
If F1 force is reversed in direction ,
F2 + F3 - F1 = ma
-F1 -F1 = ma
-2F1 = ma
F1 = (ma)/2
Explanation:
Answered by
0
Answer:In 3rd Quadrant
Explanation: As length depicts magnitude of vectors
Hence we can observe that F³ is largest in magnitude and F² is smallest. But F¹ makes the resultant force towards F². Hence the resultant force should be in 3rd quadrant.
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