Three forces p,q,r are acting ona particle in the plane the angle between p and q and that between qand r are 150 and 120 respectively then for equilibrium force s p,q,r
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Step by step solution.
1.Draw the diagram to represent P, Q and R in the plane, say OPQR, with O as origin and OP
2.Along X- axis say. O is initial point and P is terminal point for the vector P.
for other vectors Q and R.
The he angle ROP = 360(-(150+120) = 90°
Represent vector R or OR as PR', so that the line segment PR' is parallel to OR.
By triangle law P+R = OR'
OR' must be opposite and equal to Q in order to keep the
particle at O in equilibrium.
Hence, angle POR' = 30.
Let |P|, |Q| |R | bet the respective magnitudes.
Apply sine rule to for triangle OPR'
OR =|R|/sin30=|P|/sin60=|Q|
|P|/1=|Q|/2=|R|/√3
hence , ratio=1:2:√3
gireesanmkg:
How can be it possible. P/1=q/2=r/√3. So the ratio p:q:r should equal to √3:2:1
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