Math, asked by preetichourasiya1982, 22 days ago

Three –fourths of a herd of deer are grazing in the field and half of the remaining are playing nearby. The rest 9 are drinking water from the field .Find the number of deer in the herd.​

Answers

Answered by riyanshu2871
2

Q8) Half of a herd of deer are grazing in the field and three-fourths of the remaining are playing nearby. The rest 9 are drinking water from the pond. Find the number of deer in the herd.

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Solution:

Let the total number of deer in the herd be x.

According to question, x=\frac{x}{2}+\frac{3}{4}\times\left(x-\frac{x}{2}\right)+9

\Rightarrow x=\frac{x}{2}+\frac{3}{4}\left(\frac{2x-x}{2}\right)+9

\Rightarrow x=\frac{x}{2}+\frac{3}{4}\times\frac{x}{2}+9

\Rightarrow x=\frac{x}{2}+\frac{3}{8}x+9

\Rightarrow x-\frac{x}{2}-\frac{3x}{8}=9

\Rightarrow\frac{8x-4x-3x}{8}=9

\Rightarrow\ \frac{x}{8}=9

\Rightarrow x=9\times8=72

Hence, the total number of deer in the herd is 72.

Answered by NishiDubey48
6

Answer:

Let the total number of deer in the herd be x.

According to question, x=\frac{x}{2}+\frac{3}{4}\times\left(x-\frac{x}{2}\right)+9

\Rightarrow x=\frac{x}{2}+\frac{3}{4}\left(\frac{2x-x}{2}\right)+9

\Rightarrow x=\frac{x}{2}+\frac{3}{4}\times\frac{x}{2}+9

\Rightarrow x=\frac{x}{2}+\frac{3}{8}x+9

\Rightarrow x-\frac{x}{2}-\frac{3x}{8}=9

\Rightarrow\frac{8x-4x-3x}{8}=9

\Rightarrow\ \frac{x}{8}=9

\Rightarrow x=9\times8=72

Hence, the total number of deer in the herd is 72.

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