Three friends A,B and C decided to distribute the prize money worth Rs.1360 among themselves in such a way that A gets 2/3 of what B gets and B gets one-quarter of what C gets. How much A will get?
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Answered by
5
let the money distributed to C be x
amount of money received by B= x/4
amount of money received by A = 2/3*x/4
= x/6
sum-
x+x/4+x6= 1360
(12x+ 3x+ 2x)/12= 1360
17x/12= 1360
x= 1360*12/17
x= 960
Money distributed to A= x/6
= 960/6= 160
amount of money received by B= x/4
amount of money received by A = 2/3*x/4
= x/6
sum-
x+x/4+x6= 1360
(12x+ 3x+ 2x)/12= 1360
17x/12= 1360
x= 1360*12/17
x= 960
Money distributed to A= x/6
= 960/6= 160
shaheer4:
Thank u so much
Answered by
2
let the money given to 'C' be c
money given to B = 1/4c
money given to A= 2/3*1/4c
so
A+B+C= 1360
2/3*1/4c+1/4c+c =1360
2/12c+1/4c+c= 1360
2/12c+3/12c+12/12c =1360 [by taking LCM 12]
17/12c=1360
c= 1360*12/17
c=960
C=Rs960
A=2/3*1/4*960
=Rs160
money given to B = 1/4c
money given to A= 2/3*1/4c
so
A+B+C= 1360
2/3*1/4c+1/4c+c =1360
2/12c+1/4c+c= 1360
2/12c+3/12c+12/12c =1360 [by taking LCM 12]
17/12c=1360
c= 1360*12/17
c=960
C=Rs960
A=2/3*1/4*960
=Rs160
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