Math, asked by wwwshrutisharma35, 3 months ago

Three friends Atul.Bala, and Chandra were playing with 3 coins. Atut had a coin
which showed head 50% of the times .Bala had a coin which showed head with
probability 1/3, and Chandra had a coin which showed head with probability 114
All the coins looked alike. They kept the coins in a table and called their common
friend Deepti to toss any one coin. If head appeared then Deepti wins otherwise she
loses Now answer the following questions
What is the chance that Deepti wins?
a) 23/36
b) 13/36
c) 1/2
d) 1/3
What is the chance that Bala's coin was tossed by Deepti for winning the game
a) 23/36
b) 13/36
c) 9/13
d)4/13
Who possesses a fair coin?
a) Atul
b) Bala
c) Chandra
d) Deepti
Had she known whose coin she was tossing, which coin Deepti should select so that
she wins more number of times
(iv)​

Answers

Answered by shourya904
0

Answer:

D) B) D)

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Answered by rishabh6d2014
1

Answer:

(1) 1/2×1/3×1/4 ×1/3 = 13/36

(2) 13/36

(3)Atul because only fair coin shows 50% of head and tail

(4) Atul

(5) don't know

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