Question

Three gases A, B and C are present in the ratio 25%, 35% and 40% by volume in a container.
Total pressure of the gases is 3 atmospheres. Calculate the partial pressure of each gas.

Answer 1

Answer:A=0.75L

             B=1.05L

             C=1.20L

Explanation: let volume of container be 100L

volume of A=25% of 100=25L

volume of B=35% of 100=35L

volume of C=40% of 100=40L

then, mole fraction of A=

$(\frac{25}{22.4})/\frac{25}{22.4} \frac{35}{22.4} \frac{40}{22.4}$=(plz ignore a vector)

25/100

NOW partial pressure of A=25/100 x 3=0.75L

similarly do other:)