Question

Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6m each, what is the distance between Reshma and Mandip?​

Answer 1

$\huge\frak\pink{Answer}$

Draw perpendicular OA and OB on RS and SM respectively.

Let R,S and M be the position of Reshma, Salma and Mandip respectively.

AR=AS= 26=3 cm

OR=OS=OM=5 m [radii of circle]

In △OAR

OA 2+AR 2 =OR 2

OA 2 +3 2 =5 2

OA= 25−9

OA=4 m

We know that in an isosceles triangle altitude divides the base ,

So, in △RSM

∠RCS=90 o

RC=CM

Area of △ORS=

1/2 ×OA×RS

1\2xRC×OS= 1/2 ×4×6

RC×5=24

RC=4.8 m

RM=2RC=2×4.8=9.6 m

So, distance between Reshma and Mandip is 9.6 m

Answer 2

Answer:

9.6metre

Step-by-step explanation:

the distance between Reshma and Mandip is 9

6 m