Question

three girls, Roshni, saloni and manali are playing a game by standing on a circle of radius 5cm drawn in the park. Roshni throws the ball at saloni, saloni to manali, manali to roshini. If the distance between saloni and roshini, and between saloni and manali is 6 cm each. what is the distance between roshini and manali?

Answer 1

Answer:

Draw perpendiculars OA and OB on RS and SM respectively.

OR = OS = OM = 5 m. (Radii of the circle)

In ΔOAR,

OA2 + AR2 = OR2

OA2 + (3 m)2 = (5 m)2

OA2 = (25 − 9) m2 = 16 m2

OA = 4 m

ORSM will be a kite (OR = OM and RS = SM). We know that the diagonals of a kite are perpendicular and the diagonal common to both the isosceles triangles is bisected by another diagonal.

∠∠RCS will be of 90° and RC = CM

Therefore, the distance between Reshma and Mandip is 9.6 m.

Answer 2

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☆ Here we use pythagoreus theorem.

So, Distance between roshini & manali=

$\sqrt{ {6}^{2} - {5}^{2} } \\ \sqrt{36 - 25} \\ \sqrt{9} \\ 3cm$

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