Math, asked by saigayathri346, 3 months ago

Three goats are tied at the comers of a triangular plot, whose each side measures 30 m. Find the maximum area (in m?) that can be grazed by the goats outside the plot, if no region can be commonly grazed by
any two goats
562.51
565 577
112571
1125 577​

Answers

Answered by Adam514
0

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Is this full question....

Answered by Anonymous
1

Answer:

Answer

Given,

Sides of triangular field is 20m,34mand42m

Semi-perimeter =

2

20m+34m+42m

=

2

96

=48m

Area of field=

48(48−20)(48−34)(48−42)

=

48×28×14×6

=

112896

=336m

2

We know that sum of angles of triangles =180

Thus, Area gazed

=Area of sector APQ+Area of sector BRS+Area of sector CTU

=Area of semicircle with radius 7m

=

2

π

×(7m)

2

=

14

22

×(49m)

2

=77m

2

Area of field-Area of gazed

=(336−77)m

2

=259m

2

Area of ungazed is 259m

Attachments:
Similar questions