Three groups of children contain respectively 3 girls & 1 boy, 2 girls & 2 boys and 1 girl & 3 boys. One child is selected at random from each group. What is the chance that three selected consists of 1 girl and 2 boys?
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Let G1,G2 and G3 be the events of selecting a girl from 1,2 and 3 group respectively,and Let B1,B2 and B3 be the events of selecting a boy from 1,2 and 3 group respectively,Then
p(G1)= 3/4
p(G2)= 1/2
p(G3)= 1/4
by the same way
p(B1)= 1/4
p(B2)= 1/2
p(B3)= 3/4
Now probability of selecting 1 girl and 2 boys
=P[(G1B2B3) or (B1G2B3) or (B1B2G3)]
=P(G1B2B3) +P(B1G2B3) +P (B1B2G3)
=
So,the chan E of getting 1 girl and 2 boys for the group is 13/32.
p(G1)= 3/4
p(G2)= 1/2
p(G3)= 1/4
by the same way
p(B1)= 1/4
p(B2)= 1/2
p(B3)= 3/4
Now probability of selecting 1 girl and 2 boys
=P[(G1B2B3) or (B1G2B3) or (B1B2G3)]
=P(G1B2B3) +P(B1G2B3) +P (B1B2G3)
=
So,the chan E of getting 1 girl and 2 boys for the group is 13/32.
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