Math, asked by airanvaibhav24481, 1 year ago

Three groups of children contain respectively 3 girls & 1 boy, 2 girls & 2 boys and 1 girl & 3 boys. One child is selected at random from each group. What is the chance that three selected consists of 1 girl and 2 boys?

Answers

Answered by hukam0685
6
Let G1,G2 and G3 be the events of selecting a girl from 1,2 and 3 group respectively,and Let B1,B2 and B3 be the events of selecting a boy from 1,2 and 3 group respectively,Then

p(G1)= 3/4

p(G2)= 1/2

p(G3)= 1/4

by the same way

p(B1)= 1/4

p(B2)= 1/2

p(B3)= 3/4

Now probability of selecting 1 girl and 2 boys

=P[(G1B2B3) or (B1G2B3) or (B1B2G3)]

=P(G1B2B3) +P(B1G2B3) +P (B1B2G3)

=
 \frac{3}{4}  \times  \frac{1}{2}  \times  \frac{3}{4}  +  \frac{1}{4}  \times  \frac{1}{2}  \times  \frac{3}{4}   +  \frac{1}{4}  \times  \frac{1}{2}  \times  \frac{1}{4}   \\  \\  =  \frac{9}{32}  + \frac{3}{32}  +\frac{1}{32}   \\  \\  =  \frac{13}{32}  \\  \\
So,the chan E of getting 1 girl and 2 boys for the group is 13/32.
Similar questions