three hores run round circular path 1760 meter in circumference at the rate of 440 metre 352 metre and 264m per minute hence will they again be together at the straight point
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yes they can in my thinking
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Circumference of the path =1760m
Speed of first horse =440 m/min
Speed of second horse = 352 m/min
Speed of third horse =264 m/min
Time taken by first horse =t=d/rate =1760/440 =4 min
Time taken by second horse = 1760/352=5 min
Time taken by third horse= 1760\/ 264 =20/3
So time at which they all will meet =lcm(4,5,20/3 ) =20 min
So after 20 min they will meet at the starting point
Speed of first horse =440 m/min
Speed of second horse = 352 m/min
Speed of third horse =264 m/min
Time taken by first horse =t=d/rate =1760/440 =4 min
Time taken by second horse = 1760/352=5 min
Time taken by third horse= 1760\/ 264 =20/3
So time at which they all will meet =lcm(4,5,20/3 ) =20 min
So after 20 min they will meet at the starting point
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