Three horses A, B and C are in a race. A is twice as likely to win as B and B is twice as
likely to win as C. What are their probability of winning?
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Let the probability of winning of horse C is xx.
then probability of winning B is 2x2x and probability of winning A is 4x4x.
Also total probability of winning is 11.
So P(A)+P(B)+P(C)=1P(A)+P(B)+P(C)=1
\Rightarrow x+2x+4x=1\Rightarrow x=\dfrac{1}{7}⇒x+2x+4x=1⇒x=
7
1
Hence probability of winning of horses A,B, and C are \dfrac{4}{7}, \dfrac{2}{7}
7
4
,
7
2
and \dfrac{1}{7}
7
1
respectively.
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