Three identical adiabatic containers A, B and C contain helium, neon and oxygen, respectively, at equal pressure. The gases are pushed to half their original volumes.
(a) The final temperatures in the three containers will be the same.
(b) The final pressures in the three containers will be the same.
(c) The pressures of helium and neon will be the same but that of oxygen will be different.
(d) The temperatures of helium and neon will be the same but that of oxygen will be different.
Answers
Answered by
0
The correct answers are (c) and (d).
Explanation:
- The expression of adiabatic process is
- pVγ = constant = constant orTVγ-1,
where ,
- γ = CpCv is the molar heat capacities ratio at constant volume and pressure.
It is known that ,
- γ is equal to 1.40 and 1.67 for a diatomic gas and a monatomic gas, respectively. Neon and helium are monatomic gases, whereas oxygen is a diatomic gas. So, altering the gases state, that is, when the volume is reduced, this will lead to indistinguishable changes in pressure and temperature for neon and helium and that will be dissimilar for oxygen.
Similar questions