Question

Three identical balls, ball I, ball II and ball III are placed on a smooth
noor on a straight line at the separation of 10 m between balls as
shown in figure. Initially balls are stationary, Ball I is given velocity of
m's towards ball II. Collision between ball I and II is inelastic
coefficient of restitution 0.5 but collision between ball II and III is
afectly elastic. What is the time interval between two consecutive
collisions between ball 1 and 2​

Answer 1

Answer: 4s

Explanation

Let the velocity of ball one and ball 2 after collision be V1 and V2

V2 - V1 = e(u1-u2)

Hence v2-v1 = 0.5×10 .......1

And mv2+mv1 = m×10

..v2 + v1= 10 .....2

Solving 1 and 2

V1 = 2.5 and v2= 7.5

Ball 2 after moving 10 metre collides with Ball 3 elastically and stops but ball 1 moves towards ball two

time taken between two consecutive collision t =10 / 2.5 =4 seconds

Answer 2

Answer:

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