Question

three identical blocks A BA and C each of mass 2kg are connected thrugh light string passing over smooth and light pulley find the acceleration of the blocks​

Answer 1

Explanation:

for block A

therefore T - mg = ma

T = 2 ( a+g) .........(1)

for block B+C system

2 mg - T = 2ma

4 g- T = 4a......(2)

putting value of T from

1 to 2, we get

4g -2a- 2g=4a

a= g/3

for block c

mg-T= mg/3

T = 4g/3= 4×10/3= 4/3N

T= 13.3N

So, the tension in the string connecting bond is 13.3N