Question

Three identical blocks of masses m = 2kg are drawn by a force F =10.2N with an acceleration of 0.6ms–2 on a frictionless surface, then what is the tension (in N) in the string between the blocks B and C?

Answer 1

Explanation:

Let Mass A be = M1

Mass B = M2

Mass C = M3

Force = 10.2 N

Tension in the rope connecting Mass B and C is

$tension = \frac{m3 \times f}{m1 + m2 + m3}$

$= \frac{2 \times 10.2}{2 + 2 + 2} = \frac{20.4}{6} = 3.4$

Hence , the tension on string between Mass B and Mass C is 3.4 N

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