Three identical bulbs are connected as shown in figure. When switch S is closed, the power consumed in bulb Bis P. What will be the power consumed by the same bulb when switch S is opened?
1) 9P/4
2) 16P/9
3) 9P/16
4) 4P/9
Answer is Option 1. Give detailed explanation.
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11
4) 4P/9
Explanation:
Given that all bulbs are identical So voltage across bulbs = E / 2 by voltage divider rule.
So, R = V^2 / P = E^2 / 4P
When S is closed, effective resistance of B and C = R * R / (R+R) = R/ 2
Voltage across B = (R/2) / (3R/2) * E = E / 3
Power consumed by B = (E/3)^2 / R = E^2 * 4P / 9 * E^2 = 4P / 9
Option 4 is the correct answer.
Answered by
1
Answer: we get the power consumed by the same bulb when switch S is opened as 4P/9
Hence, option D is the correct answer.
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