Question

Three identical capacitors have equivalent
capacity 2 uF when they are connected in
series. If they are connected in parallel and
charged to a potential of 200V, the energy
stored in the system (in J) is​

Answer 1

Answer:

Explanation:

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Answer 2

The energy stored in the system (in J) is​ 0.36 J.

Given,

3 Capacitors of equivalent capacitance

Equivalent capacitance in series connection = 2 μF

They are then connected in parallel connection

Potential = 220 V

To Find,

Energy stored in the system

Solution,

Let the capacitance of 1 capacitor be 'x'

For series connection -

1/C = 1/C₁ + 1/C₂ + 1/C₃ + ........

1/2 = 1/x + 1/x + 1/x

1/2 = 3/x

Cross multiplying we get

x = 6 μF

Now capacitors have been connected parallely

C = C₁ + C₂ + C₃ + ........

C = 6 + 6 + 6

C = 18 μF = 18 * 10⁻⁶ F

The capacitor energy is given as

E = (1/2) * C * V²

where C is equivalent capacitance and V is potential

E = (1/2) * 18 * 10⁻⁶ * (200)²

E = (1/2) * 18 * 10⁻⁶ * 4 * 10⁴

E = 0.36 J

The energy stored in the system (in J) is​ 0.36 J.

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