three identical cells each of EMF 2 volt and unknown internal resistance are connected in parallel. this connection is connected to an external resistance of 5 ohm resistance if the terminal voltage of the cell is 1.5 volt then internal resistance of each cell is
Answers
Answer:
Nice question !!!
Explanation:
Method 1:
Since all connections are in parallel, current drawn from each cell is independent of one another,
Then taking only one such combo There is a cell with some internal resistance connected with a resistance.
E = ir + V -------From kirchoff's law
also V = iR
From this, 1.5 = 5 x i i = 0.3
2 = 0.3r + 1.5
0.5 = 0.3r
r = 5/3
Method 2:
As the cells are in parallel combo we can use the formula for net emf
E₁/r₁ + E₂/r₂ +E₃/r₃ .....
(E)net = _________________
1/r₁ + 1/r₂ + 1/r₃ +....
(E)net = 2(3/r) / (3/r)
= 2 (r)eq = r/3
E = ir/3 + V
2 = (0.3) x 3 x r/3 + 1.5
(current is multiplied by three as there is three eq arms where current splits)
we get r = 5/3
Hence internal resistance = 5/3
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