Question

Three identical cells,each of emf 2V and internal resistance 0.2 ohms are connected in series to an external resistor of 4.7 ohms. Calculate the current in the circuit.

Answer 1

R=0.2+4.7ohm
=4.9ohm

V=IR

2V=A×4.9ohm
2v=A×49/10ohm
2×10/49=I
20/49=I
0.4081632653A=I