Three identical charges (q = −5.0 μC) lie along a circle of radius 2.0m at angels of 30°, 150°, and 270°. What is the resultant electric field at the center of the circle? (Hint: Consider getting the x and y components of each electric field E.)
Answers
Given info : Three identical charges (q = −5.0 μC) lie along a circle of radius 2.0m at angels of 30°, 150°, and 270° .
To find : The resultant of electric field at the centre of circle is ...
solution : see diagram attached in figure,
electric field due to A at centre, E₁ = E(cos30° i + sin30° j) , where E = kq/r²
k = 9 × 10^9 Nm²/C² , q = 5 × 10^-6 C and r = 2m
so, E = (9 × 10^9 × 5 × 10^-6)/(4)
= 11.25 × 10³ N/C
= 11250 N
electric field due to B at centre, E₂ = E(cos150° i + sin150° j )
electric field due to C at centre, E₃ = E(cos270° i + sin270° j)
now resultant electric field at centre, Enet = E₁ + E₂ + E₃
= E(cos30° i + sin30° j) + E(cos150° i + sin150° j) + E(cos270° i + sin270° j)
= E[ √3/2 i + 1/2 j + (-√3/2)i + 1/2 j + 0 i - j]
= E[ 0]
= 0
Therefore the resultant electric field at the centre of circle is zero.
also read similar questions : Question 1.6: Four point charges qA = 2 μC, qB = −5 μC, qC = 2 μC, and qD = −5 μC are located at the corners of a square...
https://brainly.in/question/3741682
Question 1.19: A point charge of 2.0 μC is at the centre of a cubic Gaussian surface 9.0 cm on edge. What is the net ele...
https://brainly.in/question/4601117
Two point charges of +16 μC and -9 μC are placed 8cm apart in air. Find the position of the point at which the resultant...
https://brainly.in/question/16479094
