Question

Three identical charges q are placed on the vertices of an equilateral triangle. Find the resultant force acting on the charge 2q kept at its centroid. (The distance of the centroid from vertices is 1 m).

Answer 1

Answer:

total force on the charge 2q = 0

Explanation:

Given.

charge on the particle kept on the vertices of triangle = q

charge placed on the centroid of the triangle = 2q  

the distance of the centroid from the vertices of triangles = 1 m

Since the given triangle is equilateral triangle so the distance of centroid from all vertices will be same and since equal charge placed on the vertices of triangle, so according to formula of force acting on the charge 2q due to one charge q will be given by

$F\ =\ \dfrac{1}{4.\pi.\epsilon}\dfrac{q.2q}{r^2}$

the force acting on the charge 2q due to other 3 charges on the vertices will be equal and magnitude and the angle between each force will be $120^o.$

So, the resultant force of all the three forces will be zero.