Question

three identical circular loops each of radius a and with their centres at origin carrying current I each the plane of all three loops are perpendicular the magn
etic field at centre of origin will be​

Answer 1

Answer:

Please check for the attached image

Explanation:

Answer 2

Answer:

This is a simple question , don't complicate in your head :

From the Magnetic field formula we know

B = µ0i/2R

so for three perpendicular fields , it will be the vector resultant of the 3 of them,

Therefore

$B' = \sqrt{B^{2} _{1}+B^{2} _{2}+B^{2} _{3}$

      =$\sqrt{3}$ µ0i/2R

This is from today's test i suppose , Happy learning

and please mark brainliest if you understood :)