Question

Three identical cubes of side 3 cm are joined end to end. Find the total surface area of the newly formed cuboid.

GUYS HELP ME IN THIS QUESTIONS
OPTION ARE GIVEN ABOVE.​

Answer 1

Given:

• Three identical cubes of side 3 cm are joined end to end

To calculate:

• T.S.A of the newly formed cuboid.

Calculation:

By joining three cubes of each side of 3 cm end to end, we get a cuboid whose,

• Length ⇒ (3 + 3 + 3) cm ⇒ 9 cm
• Breadth ⇒ 3 cm
• Height ⇒ 3 cm

Now , as we know that :

★ $\underline {\boxed {\sf { {T.S.A}_{(Cuboid)} = 2(lb + lh + bh) }}}$

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Substituting values:

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$\sf {\dashrightarrow {T.S.A}_{(Cuboid)} = 2\[ (9 \times 3) + ( 9 \times 3) + ( 3 \times 3) \] \: {cm}^{2} }$

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$\sf {\dashrightarrow {T.S.A}_{(Cuboid)} = 2\[ (9 \times 3) + ( 9 \times 3) + ( 3 \times 3) \] \: {cm}^{2} }$

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$\sf {\dashrightarrow {T.S.A}_{(Cuboid)} = 2(27+ 27 + 9) \: {cm}^{2} }$

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$\sf {\dashrightarrow {T.S.A}_{(Cuboid)} = 2(63) \: {cm}^{2} }$

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$\boxed{ \sf {\dashrightarrow {T.S.A}_{(Cuboid)} =126 \: {cm}^{2} }}$

Hence, total surface area is $\sf { 126 \: {cm}^{2} }$

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[*Swipe left to view full calculation.]

Requored Answer :

• Option A ⇒ 126 sq. cm.

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More formulae :

• L.S.A of cuboid = 2 (l +b)h sq. units

• T.S.A of cuboid = 2(lb + ki + bh) sq. units

• T.S.A of cube = $\sf { 6{s}^{2} }$ sq. units

• L.S.A of cube = $\sf { 4{s}^{2} }$ sq. units

Answer 2

Answer:

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