Question

Three identical particles are connected by three strings as shown in fig. These particles are
revolving in a horizontal plane. The velocity of outer most
horizontal plane is v. Then T, :T2: T3 will be
- (Where T, is tension in the outer most string etc.)
ANSWER WITH CORRECT EXPLAINATION​

Answer 1

Answer:

Explanation:

According to the question we know that we have to find the ratio of tension in the three section of string.

so let's suppose angular speed of thread is equal to "W"

by each strings length.

in case of particle C= T3=mW²3l.

in case of particle B = T2- T3= mW²3l. so T2=mW²5l

in case of particle A= T1- T2 =mW²2l so T1=mW²6l.

Hence the ratio will 3:5:6. which is our answer

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