Question

Three identical particles cach of mass 0.1kg
are arranged at three corners of a square of
side 2m. The distance of the centre of mass
from the fourth corner is
1) 2/3m 2) 4/3m 3) lm 4) 8/3m​

Answer 1

Given : Three identical particles cach of mass 0.1kg are arranged at three corners of a square of

side 2m.

To find : The distance of the centre of mass from the fourth corner.

solution : see figure, here a square of sides 2 is shown. three identical particles are located each of vertices of the square.

x - component of centre of mass :

x = (m1x1 + m2x2 + m3x3)/(m1 + m2 + m3)

= (0.1 × 1 + 0.1 × -1 + 0.1 × -1)/(0.1 + 0.1 + 0.1)

= (-0.1)/(0.3)

= -1/3

y-component of centre of mass :

y = (m1y1 + m2y2 + m3y3)/(m1 + m2 + m3)

= (0.1 × 1 + 0.1 × 1 + 0.1 × -1)/(0.1 + 0.1 + 0.1)

= 1/3

Therefore centre of mass is located at (-1/3, 1/3)

fourth corner is located at (1, -1)

so, the distance between the centre of mass from the fourth corner is √{(1 + 1/3) + (-1 - 1/3)}

= 4/3 m

Therefore option (2) is correct choice.

Answer 2

Answer:

Explanation:

ans is option 3 because $\sqrt{2}$m*$\sqrt{2}$ is 2 and 2/2 is 1.