Three identical point masses, each of mass 1 kg lie in the x-y plane at points (0,0) (0, 0.2m) and (0.2m, 0) respectively.
The gravitational force on the mass at the origin is ? please explain thoroughly
Answers
Answered by
12
Answer:
Explanation:1.67×10−9(iˆ+jˆ)N
3.34×10−10(iˆ+jˆ)N
1.67×10−9(iˆ−jˆ)N
3.34×10−10(iˆ+jˆ)N
Answer :
A
Solution :
Let particle A lies at origin, particle B and C on y and x-axis respectively
F→AC=GmAmBr2ABiˆ
=6.67×10−11×1×1(0.2)2iˆ=1.67×10−9iˆN
Similarly F→AB=1.67×10−9jˆN
∴ Net force on particle A
F→=F→AC+F→AB=1.67×10−9(iˆ+jˆ)N
Answered by
5
Gravitational force F= r 2
Gm 1 m 2
Given: r=.2mm
1
=m
2
=1kg
Now force on object at O due to B, F
1
=
(.2)
2
6.67×10
−11
(1)(1)
i
^
=1.67×10
−9
i
^
Force on object at O due to A, F
2
=
(.2)
2
6.67×10
−11
(1)(1)
j
^
=1.67×10
−9
j
^
Hence net force F=1.67×10
−9
(
i
^
+
j
^
)N
solution
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