three identical polaroids sheets P1 P2 P3 are oriented so that the the pass axis of P2 and P3 are inclined at 60 degree and 90 determine intensities
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here we have to apply the formula polarisation=icos^2(theta)
so by adding angles of p2 =120i.e.(with respect to +ve x axis 60 cos +ve)
and p3=120i.e.(with respect to +ve x axis30 cos +ve)
p1 remains unchanged
so the ans is 3Icos^2(theta)/16
so by adding angles of p2 =120i.e.(with respect to +ve x axis 60 cos +ve)
and p3=120i.e.(with respect to +ve x axis30 cos +ve)
p1 remains unchanged
so the ans is 3Icos^2(theta)/16
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The intensity of P2 and P3 is 3I0/32 .
If unpolarized or circularly polarized light passes through polariser, the intensity of the output is independent of the angle between the pass axis
When unpolarised light passed through P1 then the intensity will be - I0/2 which is independent of the angle.
Intensity of light after passing through P2 = I0/2cos² 60° = I0/8
Angle between P2 and P3 = 30°.
On rotating P3 anticlockwise at an angle of 30 with respect P2, the angle between P2 and P3 will be zero.
Therefore, intensity = I0/8.
On rotating P3 anticlockwise at at angle 60° with respect P2, the angle between P2 and P3 is 30°
Therefore, intensity = I0/8cos² 30 °
= 3I0/32
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