Three identical resistances each of 3 ohm are connected in series and such 3 combination are connected in parallel. Than net resistance will be
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Answer:
If the resistances are in series then total resistance in the circuit is (3+3+3)+1=10 ohm.
So the current in the circuit is I
s
=
10
V
A. Where, V is the battery voltage.
Again, if the resistances are in parallel then total resistance in the circuit is (3∣∣3∣∣3)+1=2 ohm.
So the current in the circuit is I
p
=
2
V
A. Where, V is the battery voltage. So,
I
p
I
s
=
5
1
.
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