Three identical resistors, each of resistance R,when connected in series with a d.csource,dissipate power X.If the resistors are connected in parallel to the same d.c.source,how much power will be dissipated?
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the power dissipated will be 9X
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Answer:
Explanation:
Let V be the emf of the d.c. source in volt. RΩ be the resistance of each resistor.
In sereis, total resistance =R+R+R=3R
Power dissipated =V23R=XorV2R=3X
In parallel, total resistance, R' is given by
1R'=1R+1R+1R=3RorR'=R/3
Power dissipated =V2R'=V2R/3=3V2R
=3×3X=9X
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