three identical rings each of mass m and radius r are kept in touch with each other such that their centres form an equilateral triangle.M.I. of the system about a median of triangle is
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The MI of first ring about this axis MR2/2+MR2=3MR2/2
The MI of second ring about this axis MR2/2+MR2=3MR2/2
The MI of third ring about this axis MR2/2
So, Total MI of system is 3MR2/2+3MR2/2+MR2/2=7MR2/2
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