Question

Three identical rods are joined together as shown in
the figure. The temperature of the junction O is
0°C
100°C
20°C
30°C
60°C
50°C
40°C​

Answer 1

The temperature at junction 'O' is 40°C​.


Solution:

As we know,


100-T + 20-T=T-0

so,

120-2T=T

3T=120

So

T=40

Thus, the temperature is 40°C​.

#SPJ2

Answer 2

Answer: The temperature of the junction O is $40$°$C$.

Explanation:

• Heat flows from the higher temperature to the lower temperature.

•    Since rods are identical so they all must have same length,area and coefficient of thermal conductivity.Let T be the temperature of the junction.

              we know that,

                   $\frac{KA}{l} (100-T)+\frac{KA}{l} (20-T)= \frac{KA}{l} (T-0)$

                               $120-2T= T$

                                    $120 = 3T$

                                     $T = \frac{120}{3}$

                                  $T = 40$°$C$

#SPJ3